Question

Limits, not sure how to go about this one
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Answer 1

@zepdrix

Answer 2

approaches 0 i think.

Answer 3

it might help if u graph it

Answer 4

Won't have a graph on test... so I would rather learn how to do it without a graph

Answer 5

Is it not that we have a formula
\[\lim_{x\rightarrow \infty} \dfrac{x^n}{e^x}=0\]

Answer 6

so, no matter n is, we get 0 , right?

Answer 7

I feel so dumb now >_< that equation is the same as \(\dfrac{\sqrt x}{e^x}\)

Answer 8

\(e^{-x}=\dfrac{1}{e^x}\)

Answer 9

So anything over e^x is 0?

Answer 10

x^(anything)/e^x

Answer 11

What if we had 1/e^x?

Answer 12

I think same. :)

Answer 13

What if we had 1/e^x?
x=100, say 1 over 2.7(ish) ^100 = 7.3050565811478200070130067818609e-44
ie zero in the limit ?

Answer 14

\[e^x=1+\frac{ x }{ 1 }+\frac{ x^2 }{ 2! }+\frac{ x^3 }{ 3! }+....\]
\[\lim_{x \rightarrow \infty}\frac{ \sqrt{x} }{ e^x }=?\]
divide the numerator and denominator by \[\sqrt{x}\]
then take the limit