The variables x and y satisfy the equation 5^(y+1) = 2^(3x) By taking logarithms, show that the graph of y against x is a straight line. ii) Find the exact value of the gradient of the line and state the coordinates of the point at whch the line cuts the y-axis.
@Hayhayz Another one she didn't teach us :o
If I may help?
If you please.
With my pleasure!
Can you apply log to both sides with any base you want?
I have no idea..
\[\Large 5^{(y+1)} = 2^{(3x)}\] Is that your equation?
Yes.
Nice!
you can use logs to help you here
Do I like ln both sides to move the exponents to the front?
Take log (standard log with base of 10) for both side, you get: \[\Large \log[5^{(y+1)}] = \log[2^{(3x)}]\]
yup u got it
remember log(A^Y) = y log(A)
And one of the properties of logarithm's is \[\huge \log(x^a)=alogx\]
I got: (y + 1)log (5) = (3x)log (2)
Great!
if you proved log(A*B) = log(A)+LOG(B) then you can easily see that log(A^N) = log(A*A*A*A*A..) = LOG(A) + LOG(A) + LOG(A)+... = n log (A)
Thank you for the medal! But let's finish it firstly
or y = ?
\[\Large (y+1)*\log[5] = (3x)\log[2]\] then \[\Large (y+1)= (3x)\frac{ \log[2] }{ \log[5] }\] then \[\Large (y+1)= const*(3x)\] then \[\Large y+1= const*x\] then \[\Huge y= const*x-1\] which is an equation of straight line
I hope I helped you.
Wonderful, I got that, but didn't put the "constant" part.
Thank you for your appreciation! You can calculate it easily I think!
I did 3x - log(2)/log(5) - 1 3x - 0.5693 and so on.
algebra looks wrong
log(2)/log(5)=?
0.43067?
0.43067*3=?
AH
I think you got it!
y = 3x - 0.292?
y=(0.43067*3)x-1
Oh, I get it now, that's what confused me.
How would you find the gradient, isn't it the m value?
1.292?
Yes it is the slope/the gradient = 1.292 Brilliant!
So for the y-intercept, all I would have to do is plug in 0 for x and get y = -1? The cords would be (0, -1) ?
Excellent! I think you got it!
Wonderful, thank you so much.
You are welcome! Any Help... Any Time... Thank you for learning!
Do you have any more questions?
Actually, there's one in my notes I never finished. Want me to tag you?
If you need a help and if I am not bothering you!
Do you mind if I just type in out right now?
It is given that ln(y+1) - lny = 1 +3lnx. Express y in terms of x, in a form not involving logarithms.
Can we start in new post, please?
Yes, of course.
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