Would someone mind explaining how to solve this problem?

Question

jtm-pa · Answer

post pls

glorylove · Answer

$$\frac{ \sin \theta }{ \sqrt{1-\sin^2\theta} }$$

glorylove · Answer

I know I'm supposed to re-write it somehow by using trigonometric identities, but man, am I confused! Any tips/points in the right direction?

solomonzelman · Answer

Oh, you are supposed to write it in a most simple way.

solomonzelman · Answer

The rules you need to know (well, you need to know all, but FOR THIS CASE),
(1)  $\sin^2x+\cos^2x=1$
(2)  $\sin x / \cos x = \tan x$. $\tiny \[0.9em]$
(I am sure you know #2)

solomonzelman · Answer

I will start you off with a hint.
-------------------------
What do you get if you subtract $\sin^2\theta$ from both sides in rule #1?

solomonzelman · Answer

$\bf \sin^2\theta +\cos^2\theta\color{blue}{-\sin^2\theta}=1\color{blue}{-\sin^2\theta}$
$\bf \cos^2\theta=1-\sin^2\theta$

Correct?

solomonzelman · Answer

So, what can you do to write your expression?