I need serious help! I don't understand this at all! Someone please!
use Pythagorean theorem
I don't know how! :(
a^2+b^2=c^2 where c is the longest side of right triangle in this case length of diagonal
So once I solve it after that, do I get my equation?
wait
Yes?
hmm i was trying to attach file hmm nvm do you know what diagonal is ?
Yes
well i gtg in few minutes so hmm diagoonal is a line that intersects the opposite corner of a square http://prnt.sc/d5dd4l
okay
http://prnt.sc/d5ddcd find the length of SQ diagonal ( hypotenuse of red right triangle )
Okay, and how do I do that? I'm really lost
w0hoh look at there that's the Pythagorean theorem now all you need to do is take the s square root both sides to find the length
Okay? I'm still not quite sure.
do you know distance formula ?? you can apply that use the points S(0,0) Q(a,b) which is same as Pythagorean theorem
Okay, yes that might work :)
hmm that's it all you have to do is find the equation that can help you to find the length of diagonal which is Pythagorean theorem
How do i set up the equation?
\[\large \rm d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\] plug in (0,0)(a,b) coordinates
Okay woould I get \[d=\sqrt{b^2+a^2}\]
yes right that's the length of that line
do I further simplify or do I just leave it at that.
isn't that the same as Pythagorean theorem if you solve it for c \[a^2+b^2=c^2 \rightarrow ~~~ c=\sqrt{a^2+b^2}\]
no that's it for the next questions when they give you numbers for a and b just plug them into that equation to find the length of diagonal
Yes, it think
it is d for distance c represent the hypotenuse same idea just different letters
Okay! thanks for help Nnesha!
yw!! :=))
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