What is the area of a triangle whose vertices are R(−4,2) ,S(1,2) , and T(−5,−4)?
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OpenStudy (devonhoward15):
@563blackghost
OpenStudy (devonhoward15):
@Vijeya3
OpenStudy (vijeya3):
9 square units?
OpenStudy (devonhoward15):
let me see
OpenStudy (devonhoward15):
idk
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OpenStudy (vijeya3):
lol okay
well acc to my calculations...it is 9
OpenStudy (devonhoward15):
ohh ok... i was just making the graph
563blackghost (563blackghost):
Hmmm I got 15.20.
OpenStudy (vijeya3):
hmm lemme check it again
OpenStudy (devonhoward15):
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563blackghost (563blackghost):
I found the distance between `(-4,2) and (-5,-4)`and got \(\large{\sqrt{37}}\) in which I multiplied with 5 `(since (-4,2) and (1,2) are 5 units from each other)`.
Once I multiplied I divided by 2.
563blackghost (563blackghost):
And I got 15.20.
OpenStudy (devonhoward15):
ok 15.20 it is
OpenStudy (devonhoward15):
ohk so the anwser would be 15.20 units ^2?
OpenStudy (devonhoward15):
@563blackghost
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563blackghost (563blackghost):
Yes sir.
Though accurately it is \(\large\bf{15.2069..}\) So yea.
OpenStudy (vijeya3):
@563blackghost There is a formula for finding the are af the triangle when the three corrdinates are given.
|dw:1478805238059:dw|
so your answer is wrng i guess....