The sum of three consecutive even integers is 36. Let x represent the first integer, x + 2 represent the second integer, and x + 4 represent the third integer. Which equation can be used to find the first integer? 3x = 2x + 6 2x + 6 = 36 3x + 36 = 2x + 6 3x + 6 = 36
Help please?
"Let x be the first integer" So x is the first integer. "Sum...is 36" First + Second + Third = 36 (x) + (x+2) + (x+4) = 36 x + x + 2 + x + 4 = 36 <-- Can you simplify this
Not on my own
I'm not very familiar with simplifying integers
\[2x + 6 = 36?\]
So treat 'x' as a pencil or somethin. If you have a pencil + pencil + pencil, that's 3 pencils. So x + x + x = 3x Makes sense? So x + x + 2 + x + 4 = 3x + 2 + 4 Right? And you know how to do 2 + 6 ofc 3x + 2 + 4 = 3x + 6 And from our original equation, the left side is 36. So if we combine them: 3x + 6 = 36.
simplifying integers just mean add the numbers
*2 + 4 I mean, not 2+6 srry
add like terms
\[3x+6=36?\]
I'm sorry for giving a hard time
you are not giving a hard time! you are here to learn and we are here to help be positive
So what I posted was the right answer?
yes
*plz be right plz be right plz be right* YAAAY!!!!
important to understand steps not just get a correct answer
Can you help me with one more please?
Oh, so far I comprehend it, I also took notes
when you understand the steps you will get the correct answer except for simple mistakes in calculations
Oh
I'll remember that
open a new post with the new question
Ok
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