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how to find a function f such that f'(x)=x and the line y+x=2 is tangent to the graph of f??
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What's the slope of the given line?
m=-1
What value of x makes f'(x) = -1?
oh...i thought you ask for the slope of tangent...the question did not give any slope value...
You were doing just fine. What is the slope of the given line, m = -1 -- Perfect. What value for x gives f'(value) = -1? x = -1 What point on the line has x = -1? y = 3. There is your task. Find a function that has f'(-1) = -1 and f(-1) = 3 You might try the antiderivative.
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oh..i get it...
Let's see it... You can do it!
i got \[f(x)=\frac{ x ^{2} }{ 2 }+\frac{ 5 }{ 2 }\]
That will do!! Good work.
thank you for helping me^^
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