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Chemistry 27 Online
OpenStudy (valirium):

Balanced equation for 2H2O + O2(g)

OpenStudy (valirium):

@Elsa213 are you or anyone you know good at Chem? xD

Elsa213 (elsa213):

I can try helping.. o: What's the questions and does it have answer choices?

OpenStudy (valirium):

Well, it just asks for the balanced equation for hydrogen peroxide --> oxygen gas + water

Elsa213 (elsa213):

So no answer choices? e.e

OpenStudy (valirium):

Sadly, no ;-;

Elsa213 (elsa213):

Dang et ;~;

OpenStudy (valirium):

I know right ;-;

Elsa213 (elsa213):

@AloneS e.e

alones (alones):

As far as I know @Jamierox4ev3r AND @brittanyrolfe are good at Chem! :D I hope one of them tries to help ;3

OpenStudy (valirium):

Okay :)

HanAkoSolo (jamierox4ev3r):

Hello! This shouldn't be that difficult, I don't think

HanAkoSolo (jamierox4ev3r):

So this is a decomposition reaction, since you have a compound breaking into smaller components.

HanAkoSolo (jamierox4ev3r):

So thus far, \(H_2O_2\)-->\(H_2O+O_2\)

HanAkoSolo (jamierox4ev3r):

Now all we have to do is add coefficients to make sure the equation is balanced

HanAkoSolo (jamierox4ev3r):

\(H_2O_2\) -->\(H_2O+O_2\) **2 H **2 H **2 O **3 O There's one extra O here. So where would be a good place to add coefficients and make things even? @Valirium

OpenStudy (valirium):

Uhhh on the left side? o.o

HanAkoSolo (jamierox4ev3r):

That's one of the places you'd add a coefficient So it'd look like this \(H_2O_2\) -->2\(H_2O+O_2\) **2 H **4 H **2 O **4 O So where's the last place you need to add a coefficient? You're so close!

OpenStudy (valirium):

Would it be on the right? e.e

HanAkoSolo (jamierox4ev3r):

Correct! So based on that, what would your final balanced equation be?

OpenStudy (valirium):

I'm not good at this part ;-;

HanAkoSolo (jamierox4ev3r):

No worries, you basically got there :) Here it is: \(2H_2O_2\)-->\(2H_2O+O_2\) **4 H **4 H **4 O **4 O See how everything is even on both sides. This is your balanced equation. Does that make sense?

OpenStudy (valirium):

Ohhh! It does. Thank you for helping! :)

HanAkoSolo (jamierox4ev3r):

I'm glad it helps :) See you later

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