Question

A cart is traveling at a constant velocity of 0.70 m/s forwards. A fan that can increase the car's velocity at a rate of 2.8 m/s^2 is suddenly turned on and accelerates the cart forwards for 3.5 seconds. How fast will the cart be moving after this time?

Answer 1

@SolomonZelman @mathstudent55

Answer 2

what formula do you know?

Answer 3

acceleration = change in velocity/change in time

Answer 4

that's the one

Answer 5

and Δvelocity = final velocity - initial velocity.

You have everything. Just plug and chug to find final velocity

Answer 6

so these are the info that i have gathered so far:
change in time = 3.5 seconds
initial velocity = 0.70 m/s
final velocity = ?
acceleration = 2.8 m/s^2

Answer 7

yes

Answer 8

2.8 m/s^2 = (final velocity - 0.70 m/s) / 3.5 s

Answer 9

yes

Answer 10

now just do the algebra.

Answer 11

9.8 m/s = final velocity - 0.70 m/s
11.5 m/s = final velocity

(but the answer is 11 m/s)

Answer 12

@Nnesha

Answer 13

nvm i got 10.5 and so it rounds to 11 m/s because of sigfigs

Answer 14

thanks for the help!

Answer 15

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Answer 16

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