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Mathematics 26 Online
OpenStudy (handymani):

The test to detect the presence of the hepatitis B virus is 97% accurate for a person who has the disease and 99% accurate for a person who does not have the disease. If 0.55% of the people in a given population are infected, what is the probability that a randomly chosen person gets an incorrect result? A. 0.98455 B.0.000165 C.0.009945 D.0.001011

OpenStudy (wanell):

The probability tests to detect the presence of hepatitis B: P (presence)= 0.97 (true) 0.03 (false) P (absence)= 0.99 (true) 0.01 (false) P(infected)=0.0055 P(not infected)= 0.9945 To have an incorrect result: P[infected and false from P(presence)] + P[not infected and false from P(absence)] =0.0055*0.03+0.9945*0.01= 0.01011 The answer is 0.01011

OpenStudy (handymani):

thankss!

OpenStudy (triciaal):

error somewhere

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