Demonstrate how you can use the slope formula to write the point-slope form of an equation of a line.
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OpenStudy (candy13106):
do u know the slope formula and point slope form
OpenStudy (dallaslifebaby01):
no i don't
OpenStudy (candy13106):
ok the slope formula is \[y2-y1/x2-x1\]
OpenStudy (candy13106):
thats how u find m then u use m and plug it into the point slope
OpenStudy (candy13106):
and point slope form is \[y-y1=m(x-x1)\]
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OpenStudy (dallaslifebaby01):
hey so sorry i didn't respond, my computer crashed @Candy13106
OpenStudy (candy13106):
its ok so u get the y1, x1, and m
OpenStudy (dallaslifebaby01):
yeah i think
OpenStudy (candy13106):
ok
OpenStudy (sooobored):
slope formula
\[m=\frac{y_2 - y_1}{x_2-x_1}\]
point- slope formula
\[(y_2 -y_1) = m (x_2-x_1)\]
to go from slope formula, to point-slope
multiply both sides of the slope formula by (x2-x1) in order to remove it from the denominator and get a from similar to point-slope
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OpenStudy (skullpatrol):
An equation of a line can be found from
(a) the slope and the y-intercept,
(b) the slope and any point on the line
or (c) any two points on the line.
OpenStudy (skullpatrol):
do you want some examples?
OpenStudy (dallaslifebaby01):
that would be helpful
OpenStudy (skullpatrol):
let's start with (a)
OpenStudy (dallaslifebaby01):
okay, the slope is what it changes by right?
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OpenStudy (dallaslifebaby01):
like something decreases by 3 the slope would be 3?
OpenStudy (skullpatrol):
yes
OpenStudy (dallaslifebaby01):
okay
OpenStudy (skullpatrol):
but think of it as 3/1 = rise/run
OpenStudy (skullpatrol):
also for "decreases" it would be -3/1
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OpenStudy (skullpatrol):
does that^ make sense?
OpenStudy (dallaslifebaby01):
yes that does thank you
OpenStudy (skullpatrol):
have you seen this formula:
$$\Huge y=mx+b$$
OpenStudy (dallaslifebaby01):
yes
OpenStudy (skullpatrol):
cool
any questions?
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OpenStudy (dallaslifebaby01):
no i think i understand all this much bette enow, thank you!