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Biology 12 Online
OpenStudy (mathsucks321):

16. Using the below information, determine the amino acid chain that would result from this mRNA template: AUG CCC GGA UUA UAG. To do this, you must use the chart on pg 136.

OpenStudy (mathsucks321):

**If a DNA segment is: TAC TGA TCG ACC CCC ATA ATG AAA ATC, then the mRNA base-pairing rule is A=U and G=C; AUG ACU AGC UGG GGG UAU UAC UUU UAG , the amino acid chart is used to determine the mRNA amino acids, so: AUG=methionine, ACU=threonine, AGC=serine, UGG=tryptophan, GGG=glycine, UAU=tyrosine, UAC=tyrosine, UUU=phenylalanine, UAG=stop. Finally, tRNA completes the process by creating the anticodon, which is the original DNA strand, except the T's are replaced by U's, so the tRNA template from above would be UAC UGA UCG ACC CCC AUA AUG AAA AUC. This entire process is called transcription and translation. Together they make proteins.

OpenStudy (mathsucks321):

Sorry it always does that x.x http://prntscr.com/d8jejn

Vocaloid (vocaloid):

so, your mRNA strand is: AUG CCC GGA UUA UAG let's start with the first codon, AUG the first letter is A, so you look at your screenshot and look at the first column

Vocaloid (vocaloid):

then go to the letter "A" and find the amino acid that matches with AUG can you tell me what it is?

OpenStudy (mathsucks321):

methionine

Vocaloid (vocaloid):

good! what about CCC?

OpenStudy (mathsucks321):

proline

Vocaloid (vocaloid):

good! do you think you can finish the rest of the chain now?

OpenStudy (mathsucks321):

Um maybe

Vocaloid (vocaloid):

GGA = ?

OpenStudy (mathsucks321):

(start)methionine-proline-glycine-leucine-(stop)

OpenStudy (mathsucks321):

UAG just says stop

OpenStudy (mathsucks321):

Is that right?

Vocaloid (vocaloid):

that's correct! good job

OpenStudy (mathsucks321):

Thanks :)

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