Question

help please

Answer 1

For f(x) = 0.01(2)x, find the average rate of change from x = 2 to x = 10.

Answer 2

1.275
8
10.2
10.24

Answer 3

Could I help you?

Answer 4

yes please

Answer 5

That is with my pleasure!

Answer 6

Is your function looks like that:
\[\large f(x)=0.01(2^x)\]

Answer 7

yes

Answer 8

Do you know what is "the average rate of change"?

Answer 9

does it mean you have for example 3, 4, 5, 6 then add then divide by 4 because that is how many numbers there are????

Answer 10

No, Mam!
"the average rate of change" means the slope of a function!

Did you study limits?

Answer 11

oh sorry :( no i didnt but in my lesson i did learn the average rate of change i just thought you meant how do i get the average in general

Answer 12

can you please explain to me the process to this question @3mar

Answer 13

"The average rate of change" does not mean the average!

Tell me how is it looks like to you!?

Answer 14

okay i understand i made a mistake i misunderstood you

Answer 15

No problem at all!
What matters is that you got the idea!

Answer 16

i think the answer is 8 am i correct ???

Answer 17

How can you reach that answer?
Can you share your works/steps, please?

Answer 18

𝟢.𝟢𝟣(𝟤)^𝟣𝟢−𝟢.𝟢𝟣(𝟤)^𝟤/𝟣𝟢−𝟤

Answer 19

Did you take derivatives at your class?

Answer 20

yes did i do something wrong

Answer 21

What you did is just substitution in the function without do a derivation of it!
Two ways to solve such proble:
- you may sub. in limit formula of "the average rate of change" with f(x) and f(x+h).
or
- derive the function and then sub, with the two values of x after that to get the "the average rate of change" between two points.


What are you familiar with?

Answer 22

sorry i was praying

Answer 23

i am familiar with both but like to do the first method

Answer 24

did i do something wrong? :(

Answer 25

No problem!
You are a good Muslim.

So you are not sorry for praying!
Not at all!

Answer 26

Please, answer that:

f(x) = 0.01(2)x x = 2 to x = 10.
f(2)=??
f(10)=f(2+8)=??
h=x_2-x_1=??

Answer 27

f(x) = 0.01(2)x x = 2 to x = 10.
f(2)= 0.04
f(10)=f(2+8)=0.2
h=x_2-x_1=??<<< i dont understand the signs

Answer 28

@3mar ?

Answer 29

Sorry for late.

Answer 30

would it be A?

Answer 31

f(10)=f(2+8)=10.24* sorry i messed up there

Answer 32

f(10)−f(2)/10−2=10.24−0.04/10−2= A

Answer 33

No sister!
f(10)=f(2+8)=0.2
not correct
I mean:
for x=10
\[f(10)=0.01*(2^{10})=0.01*1024=10.24\]
also for x=2
\[f(2)=0.01*(2^2)=0.01*4=0.04\]
and for h:
\[h=x_2-x_1=10-2=8\]

Now the limit section:
\[\lim_{h \rightarrow 0}=\frac{ f(x+h)-f(x) }{ h }=\frac{ f(10)-f(2) }{ h }=\frac{ 10.24-0.04 }{ 8 }=?~?~?\]

Answer 34

yes that is what i said just now :) and i got 1.275

Answer 35

i would really appreciate it if you would confirm my answer

Answer 36

@3mar

Answer 37

How did you get A and you did that wrong? "f(10)=f(2+8)=0.2"

Answer 38

\(\color{#0cbb34}{\text{Originally Posted by}}\) @OtherWorldly
f(10)=f(2+8)=10.24* sorry i messed up there
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 39

if you look up you will see that i corrected myself

Answer 40

so are you saying A is incorrect??

Answer 41

and B????

Answer 42

C or D do not make sense so it has to be A.......am i right

Answer 43

So That makes sense now!

Answer 44

"so are you saying A is incorrect?? "

No I did not say that!

It is the correct one!

Answer 45

\[\Huge\color{red}\checkmark\]
Congratulations! ♥

Answer 46

thank you

Answer 47

No problem at all!
You are welcome!
Any Help... Any Time...