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Mathematics 25 Online
OpenStudy (becca9898):

A long distance runner starts at the beginning of a trail and runs at a rate of 4 miles per hour. Two hours later, a cyclist starts at the beginning of the trail and travels at a rate of 14 miles per hour. What is the amount of time that the cyclist travels before overtaking the runner?

OpenStudy (becca9898):

So I know the basics, but I just need help walking through these one last time. Thank you to everyone who has helped me. Seriously!

OpenStudy (518nad):

okay so lets start with the runner's distance

OpenStudy (518nad):

what is the runners distance as a function of time

OpenStudy (becca9898):

D= 4x for equation 1 and D= 14(x+2) for equation 2?

OpenStudy (518nad):

close

OpenStudy (becca9898):

Would it be 14(x-2)?

OpenStudy (518nad):

yes

OpenStudy (518nad):

can i suggest something

OpenStudy (becca9898):

Ok!! That makes a ton more sense. So, 4x=14x-28

OpenStudy (518nad):

yes

OpenStudy (becca9898):

2.8 would be the distance?

OpenStudy (518nad):

something doesnt make sense

OpenStudy (becca9898):

So my answer would be 11.2?

OpenStudy (518nad):

14t=4t+8

OpenStudy (becca9898):

How did you get that?

OpenStudy (518nad):

okay so after 2 hours, the runner is at 8 miles right

OpenStudy (518nad):

we willl consider this time the starting point of time |dw:1479691999159:dw|

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