Question

HELP ASAP

Answer 1

What is the question?

Answer 2

What does ASAP mean?

Answer 3

As soon as possible. @SolomonZelman

Answer 4

I meant to emphasize, or to allude to the delay.

Answer 5

Which question do you want, #1, #2, or both?

Answer 6

yes, #1 is right.

Answer 7

yes, you are right!

Answer 8

-24!?

Answer 9

@SolomonZelman

Answer 10

I don't know yet, but I will do this problem in a few eye blinks right now, give me some time please.

Answer 11

We want the coefficient of the \(x^2\) term in the \(f''(x)\), and we know that if \(x^2\) is in the second derivative, then we are looking for the function's \(x^4\) term.

Answer 12

Which term is this going to be?
\(x^3\times (-8x)+(3x^2)\times (-6x^2)\)

Answer 13

\(=(-8-18)x^4=-26x^4\)

Answer 14

So your result is sadly, but obviously already incorrect, because the magnitude of your coefficient for \(x^2\) in \(f''(x)\) is smaller than the current coefficient of the \(x^4\) term. Right?

Answer 15

having found the \(x^4\) term in \(f(x)\) to be \(-26x^4\), what is the coefficient of \(x^2\) in the second derivative?

Answer 16

\(\color{black}{\displaystyle D^2[-26x^4]=? }\)

Answer 17

(What is the second derivative of -26x^4 ?)

Answer 18

omg i already worked it out am i right or not?????> @SolomonZelman

Answer 19

I just told you were not right.

Answer 20

-26 is the current coefficient of \(x^4\) term in the \(f(x)\).

Answer 21

So, if the coefficient of \(x^4\) in \(f(x)\) is \(-26\), then the coefficient of \(x^2\) in \(f''(x)\) is? (All you got to do, is to differentiate twice)

Answer 22

Do you know how to take a derivative?

Answer 23

What is the (first) derivative of \(-26x^4\) ?

Answer 24

yes

Answer 25

and what is the (first) derivative of -104x^3 ?

Answer 26

(Note: The first derivative of -104x^3, is the same thing as the second derivative of -26x^2.)

Answer 27

Yes.

Answer 28

So the desired coefficient is ?

Answer 29

x^2

Answer 30

???? @SolomonZelman why did u leave

Answer 31

Something happened, and I had to refresh.

Answer 32

yes, -312 is correct.

Answer 33

Yes, I am sure. yw

Answer 34

Yes, for #3.

Answer 35

Yes, for #4.

Answer 36

ah yes thank you so much!! can ia sk you some more calculus questions later on?????

Answer 37

Anybody can definitely ASK me anything ... whether I answers depends on 3 criteria: time, willingness, and knowledge.

Answer 38

I don't want to give any empty promises, will see how it goes.
YW