Question

help

Answer 1

@SolomonZelman

Answer 2

@Jamierox4ev3r

Answer 3

@mathstudent55

Answer 4

@Hayhayz

Answer 5

@osprey

Answer 6

@mhchen

Answer 7

@hero

Answer 8

@Nnesha

Answer 9

@Seratul

Answer 10

and I can't help?

Answer 11

encl is a rough thing. I hope it's SOMEWHERE near being right. I seems to me to be a bit disjointed ...

Answer 12

Since this is a piecewise function, you need to graph it one step at a time and keep in mind the equalities and inequalities.

Let's start with graphing the first part of the piecewise function:
\(1. ~f(x)=3x-5 \) if \(x \leq -1 \)

How does the graph of y = 3x-5 usually look?
Something like this, right?


Now, since we need our function to be y = 3x-5 for all values of x less than or equal to -1, we basically cut this function that we just made to only include the parts we need.



Does this make sense?
Try to attempt the next part of the piecewise function:
\(2. ~f(x) = -2x+3\) if \(-1 < x < 4\) [Note: here we don't include the values of x = -1 and x = 4 and hence we put a white dot instead of a black one]

[Protip: read this http://www.mathsisfun.com/sets/functions-piecewise.html for some more info on piecewise functions]