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Mathematics 25 Online
OpenStudy (chillydog0):

Which statement can be proved true using the given theorem? Segment BF = 9 Segment BD = 18 Segment BD = 20 Segment BF = 24

OpenStudy (chillydog0):

Theorem: A line parallel to one side of a triangle divides the other two proportionately. In the figure below, segment DE is parallel to segment BC and segment EF is parallel to AB:

OpenStudy (chillydog0):

OpenStudy (chillydog0):

I got 24 by cross multiplying and then dividing.

OpenStudy (mathstudent55):

Using the theorem, set up a proportion for BF and a proportion for BD. Solve the proportions, and find their lengths. Then choose the correct option.

OpenStudy (mathstudent55):

Which proportion did you set up?

OpenStudy (chillydog0):

12*30 / 15 360/ 15 24

OpenStudy (mathstudent55):

That is not a proportion. A proportion is two ratios that are equal to each other. Also, which length are you solving for, BF or BD?

OpenStudy (chillydog0):

I am so confused

OpenStudy (mathstudent55):

Let me redraw your triangle to simplify it. You have two parallel segments, so there are two possibilities with the proportions. Let me draw a triangle with only one parallel side and explain the theorem to you that way.

OpenStudy (chillydog0):

Okay thank you.

OpenStudy (mathstudent55):

Here is a triangle. |dw:1479832770122:dw|

OpenStudy (mathstudent55):

Now I'll draw a segment parallel to side BC that intersects sides AB and AC. |dw:1479832832995:dw|

OpenStudy (mathstudent55):

Segment DE is parallel to side BC.

OpenStudy (chillydog0):

SO 12 and 15

OpenStudy (mathstudent55):

According to the theorem above, then the split sides have proportional segments. This is what that means: \(\dfrac{AD}{DB} = \dfrac{AE}{EC} \)

OpenStudy (chillydog0):

Okay let me solve it

OpenStudy (mathstudent55):

In each split side, you find the ratio of the two segments of the side. If you write the ratios in the same order, then the ratios are equal. That's what it means for the segment of the sides to be proportional.

OpenStudy (chillydog0):

I got 20.

OpenStudy (mathstudent55):

Now we use this figure for your problem and write only the pertinent segment lengths for now. |dw:1479833090426:dw|

OpenStudy (mathstudent55):

We can use our proportion to solve for BD.

OpenStudy (mathstudent55):

\(\dfrac{AD}{BD} = \dfrac{AE}{CE} \) \(\dfrac{12}{BD} = \dfrac{15}{25} \) Notice only one unknown, so we can solve for BD. \(BD = \dfrac{12 \times 25}{15} \) \(BD = 20\)

OpenStudy (chillydog0):

I already did that. Thank you though.

OpenStudy (chillydog0):

You helped me get there!!

OpenStudy (mathstudent55):

That is the answer. Now out of curiosity, let's look at what BF is. |dw:1479833326921:dw|

OpenStudy (mathstudent55):

\(\dfrac{30}{BF} = \dfrac{25}{15} \) \(BF = \dfrac{30 \times 15}{25} \) \(BF = 18\)

OpenStudy (chillydog0):

Thank you!!

OpenStudy (mathstudent55):

BF = 18, and no answer states that, so the correct choice is C.

OpenStudy (mathstudent55):

You're welcome.

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