Question

plzzz hepl will medal and fan!!!!!
Make a table of ordered pairs for the equation.

y=12x−3

Answer 1

So for this you are going to choose values to plug in for x and then plug them in and find y. For example if x=0 then you plug it into the equation and get \[y=12\times0-3\]
So y=-3 and you can start a table
X Y
0 -3
1 9
2 21
3 33
To get the other values you just plug the x into the equation and simplify.

Answer 2

im sorry that that was suposed to be \[\frac{ 1 }{ 2}\]

Answer 3

not 12

Answer 4

Ok, so it it is \[\frac{ 1 }{ 2 }\]
You will wan to choose all even numbers for the x-values so that you don't have to deal with fractions or decimals in your answers.
So start with 0, because it is easiest.
\[y=\frac{ 1 }{ 2 }\times0-3\]
Which is still going to be -3. And that starts your table
X Y
0 -3
2 -2
4 -1
6 0

Answer 5

this s the question who do i graph that

Answer 6

that what i thin the answer is an i right

Answer 7

You have the y-intercept (where the line goes through the up and down axis) correct, however the spot for the line going through the x-axis (the one that goes left and right) is not in the right spot. Look at the table again and see where y=0 and that will show you the value where the line should go through the x-axis.

Answer 8

this

Answer 9

So the point you have at (0,-3) is correct. Now try plotting the other point that has a zero in it, because the line should not be just up and down.

Answer 10

So you have put a point at (0,0), but look at the table, that is not one of the points on the table. You want to look at the point (6,0)

Answer 11

so graph (6,0)

Answer 12

Yes, that point along with the point (0,-3) are the more important ones on the graph. Whenever there is a 0 in the ordered pair it means that that point is important.

Answer 13

that

Answer 14

Ok, now just get rid of the point at (0,0) because that is not part of the line and you should then have the line you need.

Answer 15

this

Answer 16

There you go!

Answer 17

can u check this other question for me

Answer 18

sure

Answer 19

So the equation is \[y=-\frac{ 1 }{ 2 }x-4\]
So you want to start with plugging in x=0 and you will get
\[y=-\frac{ 1 }{ 2 }\times0-4\]
so y=-4
Which makes the point (0,-4). Now do you have that point on this graph? Look at the dign carefully.

Answer 20

*sign

Answer 21

You got a kik