Question

Help pls will award medal!
Simplify the expression
-5 + i/ 2i

Answer 1

Does it work out like this?
-5+i/2i
-2i*-5+i/2i*-2i
10i - 2i^2/-4i^2
10i-2/4
-0.5 + 10i?

Answer 2

-5+i square/2

Answer 3

well its really 10i-2 (divided) 4

Answer 4

so 10i - 2/4 is the answer? so my steps are correct?

Answer 5

yes

Answer 6

First, you have to be clear what it is you are writing.

You wrote this: -5 + i/ 2i which means \(-5 + \dfrac{i}{2i} = -5 + 1/2 = -9/2\)

I'm guessing you meant : (-5 + i)/ 2i which means \(\dfrac{-5+i}{2i} = \dfrac{(-5+i)}{2i}\cdot\dfrac{i}{i} = \)

\(= \dfrac{(-5i + i^{2})}{2i^{2}} = \dfrac{(-5i + (-1))}{2(-1)} = \dfrac{-5i - 1}{-2} = \dfrac{5i + 1}{2}\)

You can continue to meet odd requirements from your teacher, after that,
maybe 1/2 + (5/2)i.

Second, you should simplify before you think you are done.

Answer 7

Note: It isn't necessary to use the Complex Conjugate unless there is a Real Portion.

1 + i requires multiplication by 1- i.
0 + i does not require multiplication by 0 - i. Simply "i" will do.

Answer 8

@karleighxxvictoria and @tkhunny thx! I got it!