Question

what is the complex root of x^2-9x^2+20=0

Answer 1

apply the quadratic formula

Answer 2

is that ax^2+bx+c=0?

Answer 3

Wait, is the question supposed to be

x^2 - 9x^2 + 20 = 0
or
x^2 - 9x + 20 = 0
?

Answer 4

there is no complex root as disc.=b^2-4ac>0

Answer 5

If there are two terms of x^2, then you should simplify them

Answer 6

It is x^2-9x^2+20=0

Answer 7

simplify
x^2 - 9x^2
i.e.
(1-9)x^2

Answer 8

so -8x^2+20=0

Answer 9

yeah

Answer 10

then get the x term to the other side

Answer 11

20=8x^2

Answer 12

now divide by 8

Answer 13

2.5=x^2

Answer 14

yes, but express 2.5 as an inproper fraction

Answer 15

5/2 = x^2

now take the square roots of both sides

Answer 16

I think if the question is asking for complex roots, then the question is actually \(\color{black}{\displaystyle x^2-9x+20=0 }\), because the way it is written right now, the roots are not complex.

Answer 17

Well, they are complex, but not complex exclusively.

Answer 18

the solution are real either way, and real numbers are a type of complex number

Answer 19

oh yes, right. 4.5^2>20.

Answer 20

My completing the square thinking gone a little off. Sorry:)

Answer 21

im not sure how to divide the square root

Answer 22

x^2 = 5/2
x = ±√(5/2)

Answer 23

that's two roots x = √(5/2) and x = -√(5/2).

both of these are real numbers

Answer 24

so then that is the final answers correct? One positive and the negative?

Answer 25

yeah, they don't simplify into nicer forms unfortunately

Answer 26

Thank you I appreciate your help.