What is the equation of a line, in point-slope form, that passes through (-2, -6) and has a slope of 1/3
A y+2=1/3(x+6)
B y+6=1/3(x+2)
C y−6=1/3(x−2)
D y−2=1/3(x−6)

Question

What is the equation of a line, in point-slope form, that passes through (-2, -6) and has a slope of 1/3
A y+2=1/3(x+6)
B y+6=1/3(x+2)
C y−6=1/3(x−2)
D y−2=1/3(x−6)

dottiecat · Answer

I'm having trouble trying to find the answer

mathstudent55 · Answer

Start with the point-slope form of the equation of a line.
Can you show it?

dottiecat · Answer

I do not understand. Sorry...

dottiecat · Answer

oh wait,

mathstudent55 · Answer

Ok. Let's cover the basics.

The point-slope form of the equation of a line is

$y - y_1 = m(x - x_1)$

where $(x_1, y_1)$ is a point on the line and $m$ is the slope of the line.

mathstudent55 · Answer

Ok so far?

dottiecat · Answer

Yes, I'm used to calling it slope formula.

dottiecat · Answer

Just a second, I might've figured out the answer.

mathstudent55 · Answer

The slope formula is a different thing.
That is the formula you use to find the slope of a line given two points on the line.

Back to this problem.
You are given a point.
You have point (-2, -6).
The point in the equation is $(x_1, y_1)$
That means $x_1 = -2$, and $y_1 = -6$
You are also given the slope $\dfrac{1}{3} $.

Just plug those values into the point-slope form I gave you above, and that is the  equation of the line.

mathstudent55 · Answer

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