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Mathematics 19 Online
OpenStudy (weaver):

Is this correct? http://prntscr.com/daz4s6

OpenStudy (tkhunny):

PR is the hypotenuse. It must be greatest of the three sides.

OpenStudy (misty1212):

HI!!

OpenStudy (misty1212):

\[\sqrt{12^2+16^2}\]will get it

OpenStudy (weaver):

Hello : ) I got 28

OpenStudy (misty1212):

hmm no

OpenStudy (misty1212):

not \(12+16\) but rather \[\sqrt{12^2+16^2}\] square first, then add,then take the square roog

OpenStudy (misty1212):

root

OpenStudy (tkhunny):

\(\sqrt{12^{2} + 16^{2}} \ne 12 + 16\)

OpenStudy (misty1212):

or memorize the mostfamostest of all right triangles \(3-4-5\) if you multiply all by 4, you get \(12-16-?\)

OpenStudy (weaver):

oh okay so 144+ 256= √400=20

OpenStudy (weaver):

Thank you!

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