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PR is the hypotenuse. It must be greatest of the three sides.
HI!!
\[\sqrt{12^2+16^2}\]will get it
Hello : ) I got 28
hmm no
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not \(12+16\) but rather \[\sqrt{12^2+16^2}\] square first, then add,then take the square roog
root
\(\sqrt{12^{2} + 16^{2}} \ne 12 + 16\)
or memorize the mostfamostest of all right triangles \(3-4-5\) if you multiply all by 4, you get \(12-16-?\)
oh okay so 144+ 256= √400=20
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