help??
than you can writing x-y=x+2 2x-y=4x+2y than solve this system for x and y
x-y = x+2 subtract from both sides x so what will get ?
-2?
what is this -2 ?
x-y=x+2 = -2?
subtract from both sides x so what will get ?
?
x-y-x = x+2-x do you can continue it now ?
Make certain you know where that set of simultaneous equations came from. The hypotenuse of one triangle equals the hyp. of the other (and so on). You must now solve this system of linear equations. How have you done that in the past? elimination? substitution? graphing? Think back.
exactly @mathmale GREAT ! thank you
But i'm not sure if i'm doing it right.
How do I do it?
Jump in and do something. Share what you have done. Then J or I would be glad to respond further. Please involve yourself. Thanks to j, you already have 2 simultaneous equations. How have you solved such sets of simultaneous equations in the past?
Hint: If you had x + y = 7 x - y =2 and had to solve for x, you'd add the 2 equations together. This gives you 2x = 9. Dividing both sides of this equation by 2, we get x = 9/2. You can find y by substituting 9/2 for x in either of these 2 equations. Please, get involved, share something. It's OK to make mistakes here...but do something!
@Rz172 If you "jump in and do something", helpers will help you continue. If you don't show anything, helpers will not continue to finish the problem while you sit and watch! lol So your choice!
@Rz172 If you "jump in and do something", whether it's right or wrong, helpers will know where to start, and where you got stuck. They will help you continue. If you don't show anything, helpers will not continue to finish the problem while you sit and watch! lol That's why helpers leave, one after another! :( Your choice!
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