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Chemistry 17 Online
alones (alones):

5 8 10 12

alones (alones):

Man fail.. How many atoms are in \(2 Al_{3}O _{2}\)

OpenStudy (aaronq):

So this is kinda like math, such that, you distribute the coefficient across each atom in the formula and you multiply it by the subscript. \(\sf 2(3~Al+2~O)=6~Al+4~O\)

alones (alones):

O that should be \(10\) @AARONQ

OpenStudy (aaronq):

YUP 100%

alones (alones):

Whew 3rd one right e-e

OpenStudy (aaronq):

what about this one? \(\sf 3~Ca(OH)2\)

OpenStudy (aaronq):

wait 2 is subscript. \(\sf 3~Ca(OH)_2\)

alones (alones):

wait you want me to solve this also? D:

OpenStudy (aaronq):

yes

OpenStudy (aaronq):

>:D for practice

alones (alones):

So \(5\) atoms?

OpenStudy (aaronq):

\(\sf 3(1~Ca+2~O+2~H)=3~Ca+6~O+6~H\)

alones (alones):

R.i.p I don't understand.

OpenStudy (aaronq):

the 2 on the outside of the bracket multiplies the whole bracket.|dw:1480384397244:dw| These formulas make more sense when you draw them

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