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Mathematics 22 Online
OpenStudy (julyahx1):

Look at the figure shown below:

OpenStudy (karleighxxvictoria):

? it just says look at the figure below!

OpenStudy (julyahx1):

OpenStudy (julyahx1):

Patricia is writing statements as shown to prove that if segment ST is parallel to segment RQ, then x = 35. Statement Reason 1. Segment ST is parallel to segment QR Given 2. Angle QRT is congruent to angle STP Corresponding angles formed by parallel lines and their transversal are congruent 3. Angle SPT is congruent to angle QPR Reflexive property of angles 4. Triangle SPT is similar to triangle QPR Angle-Angle Similarity Postulate 5. 28:40 = Corresponding sides of similar triangles are in proportion Which of the following can she use to complete statement 5? x:15 x:(x + 15) 28:15 28:(x + 15)

OpenStudy (julyahx1):

i think its B but I'm not 100 percent sure

OpenStudy (julyahx1):

it might be d

OpenStudy (julyahx1):

@3mar

OpenStudy (3mar):

Welcome back! \[\Huge\color{red}ツ\]

OpenStudy (julyahx1):

yeah hey! lol. Think you can help me on this one? Not sure if its b or d

OpenStudy (3mar):

I will go now ... sorry but i will be back within 15 min IN Sha' Allah but it is not d and I will show you why!

OpenStudy (julyahx1):

So it's B right? B is what i was thinking

OpenStudy (daniyil_the_spy):

ok

OpenStudy (daniyil_the_spy):

ill try

OpenStudy (julyahx1):

Thank you

OpenStudy (daniyil_the_spy):

I also think Its B

OpenStudy (daniyil_the_spy):

All the others look wrong to me

OpenStudy (julyahx1):

@Rz172 Do u think it's B too?

OpenStudy (julyahx1):

you there?

OpenStudy (3mar):

To be sure, here is the result of similarity.. all corresponding sides are proportional! \[\LARGE {\frac{ PS }{ PQ }=\frac{ PT }{ PR }=\frac{ ST }{ QR }\\ \frac{ 28 }{ 28+12 }=\color{DarkSlateBlue }{\frac{ x }{ x+15 }}\\\frac{ 28 }{ 40 }=\color{SlateBlue }{\frac{ x }{ x+15 }}}\] **Sorry for late. The electricity was off!

OpenStudy (matthew120):

idek im in 7th

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