A baseball is thrown up into the air. The ball's height in feet is modeled by the equation h(t) = -16t^2 + 32t + 10. h is height, t is time in seconds. How many seconds after the ball is thrown will it reach its maximum and minimum height? Need help!

Question

logo · Answer

its 9 not 10 for the equation 
-16t^2 + 32t + 9

welshfella · Answer

convert to vertex form:-

-16t^2 + 32t + 9
= -16[ t^-  2t] + 9
=   -16[ (t - 1)^2 - 1] + 9
=  -16(t - 1)^2 + 25

the maximum height is 25 after 1 second  ( when t = 1)

welshfella · Answer

it will take the same time to reach the ground  as it took to reach maximum 
so minimum time =  ?

logo · Answer

minimum time = 1 ? @welshfella

logo · Answer

@welshfella oh wait I'm sorry, it only asked for its maximum height not the minimum. I was so confused about the minimum. I even tried it this way by finding the vertex first using t = -b/2a and got 25 feet in the end.