Question

help pls I'll give u medal!

Franklin rolls a pair of six sided fair dice with sides numbered 1 through 6.
The probability that the sum of the numbers rolled is either even or a multiple of 5 is ____. the probability that the sum of the numbers rolled is either a multiple of 3 or 4 is ____

11/18, 13/19, 11/36, 13/36 for the 1st question

1/12, 1/3, 1/4, 5/9, 7,12 for the second Question

Answer 1

not a very fun problem

ok, sum of number must be either even, or a multiple of 5
starting with even restriction
only odd + odd = even & even +even =even
restriction of multiple of 5- sum must be either 5 or 10

so if you want to break it up
if you roll a 1 with the first dice (1/6 probability), you would need to roll either a 1,3,5, and 4 (4/6) in order to satisfy your conditions
so the probability of satisfying the conditions if 1 is rolled with the first dice is 4/36

ok, now if you roll a 2 with the first dice, what would you need to roll on the 2nd to satisfy the even and multiple of 5 conditions

etc
then add up the probabilities

then add up all the probability