Question

HELP PLEASE WILL MEDAL AND FAN

Answer 1

@Daniyil_the_spy

Answer 2

whaaaaat

Answer 3

can u help please

Answer 4

frist one yw

Answer 5

thx

Answer 6

Use the index laws - power raised to another power, and a product raised to a common power:
\[(a^m)^n = a^{mn}\]
\[(ab)^m = a^m b^m\]

So for our case the power of 1/4 applies to both the m and n bases and we multiply the indices together (8 x 1/4 = 2 and -4 x 1/4 = -1):
\[(m^8n^{-4})^{\frac{ 1 }{ 4 }} = m^2 n^{-1} \]
Also note
\[n^{-1} = \frac{ 1 }{ n }\]
so our final answer is \[\frac{ m^2 }{ n }\]

Make sure you can see the steps.