physics question
@osprey you know how to do it ?
@KittyKat Hi kitty ... sort of but it'll take a bit longer than 5 minutes ...
It seems to want the ABSOLUTE error, which is different, I think, from the percentage error. I guess that the bits on the LHS are the offers of the choices of the answers ? and I start by going off line to doodle with it
okey
could be e as a first guess. radius is to .02 10^-3 (.02 millimetres) radius is multiplied by a constant. So there's no "other errors" involved (as long as you watch out for pi) So if the first line is the abs error in the meas of radius (micrometer screw gauge of some such ?) then the thing is unchanged ???????
they used the radius to get C so the uncertainty in radius \(\Delta r\) will flow through that calculation \(C = 2 \pi r\) \(C + \Delta C = 2 \pi (r + \Delta r)\) \(\Delta C = 2 \pi r + 2 \pi \Delta r - C \) \(\Delta C = 2 \pi \Delta r \) looks like g
Yep it's G
how?
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