Question

This us really easy but im dumbing down. How do u integrate this?

Answer 1

4-y dy

Im on my phone so i cant put my integral sign in. But how do u integrate that indefinite integral?

Answer 2

\[\int\limits {(4-y )}dy = \int\limits 4 dy - \int\limits y dy\]

Answer 3

\[\int\limits x^n dx = \frac{1}{1+n}x^{n+1}\]

Answer 4

Oh thts right! So 4y - (y^2)/2?I took out the 4 as a whole number and forgot to put the y in. That's what threw me off. Thanks!

Answer 5

\[\int\limits 4 dy = 4 \int\limits 1 dy\]
\[1= y^0\]
\[\int\limits y^0 dy = \frac{1}{0+1} y^{0+1} = y\]
\[\int\limits 4 dy =4 \int\limits 1 dy = 4y\]

Answer 6

yup, i see no issues with your integration

Answer 7

Thank you!