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Suppose that ln2=a and ln3=b. Use properties of logarithms to write each log in terms of a and b. -> ln6
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6=3*2 yes ?
do you know this property of logarithms ? log a +log b = log a*b
I am not sure to be honest but i have the book with me and it shows me what it should be but i just want to know how to work it out. The actual answer is a+b
ln6 = ln(3*2) ln(3*2) = ln3 +ln2 ok. ?
ln6 = ln3 +ln2
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ok and waht if it was b-a
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