Question

I NE

Answer 1

than f(x) = x^4 -5 so

f(x+5) = ? just substitute the x+5 in place of x but dont forget the 3 bc. you need getting f(x+5)+3

Answer 2

yes for the first one sure

Answer 3

i ve said you above what you need to do

f(x+5) = (x+5)^4 +5

f(x+5)+3 = (x+5)^4 +5+3 = ?

Answer 4

sorry there is minus 5

Answer 5

so I got (x+5)^4

Answer 6

f(x) = x^4 -5

f(x+5) = (x+5)^4 -5

Answer 7

you need getting f(x+5) +3 = ?

Answer 8

if you could write it all in one that'd be best to help me learn

Answer 9

f(x) = x^4 -5

g(x) = f(x+5) +3

f(x+5) = (x+5)^4 -5

g(x) = (x+5)^4 -5 +3

g(x) = (x+5)^4 -2

do you understand it now ?

Answer 10

so that would be the simplified equation?

Answer 11

please help this is the last one i really need help learning the steps!!

Answer 12

no

(x+5)^4 = (x+5)^2 *(x+5)^2

Answer 13

you need to know formula

(a+b)^2 = a^2 +2ab +b^2

Answer 14

for the first one bc. this not is ended again so there

Answer 15

no

you need using this formula and make the calculi

Answer 16

@mathmate @pooja195 @satellite73 @sooobored ASAP please!

Answer 17

substitute g(x) for x in f(x)

Answer 18

and then simplify

Answer 19

by like replacing x with the actual function g(x)

Answer 20

@satellite73 @518nad

Answer 21

@mathmate

Answer 22

what question are you doing?

Answer 23

let me enlarge it for a second

Answer 24

i need explaining on both though very badly

Answer 25

\[f(x)=\frac{2x}{2+x}\]
\[g(x)=\frac{2x}{2-x}\] that one ?

Answer 26

and you want \[f(g(x))\] right?

Answer 27

yes

Answer 28

first step it to replace the \(g(x)\) in \[f(g(x))\] by what it actually is
which in this case is \(\frac{2x}{2-x}\) so step one is to write \[\huge f(g(x))=f\left(\frac{2x}{2-x}\right)\]

Answer 29

ok

Answer 30

now are you familiar with "cut and paste" like in some document?

Answer 31

do you use control c, control v or something else?

Answer 32

yes just c control

Answer 33

for copy, and control v for paste or something else for paste?

Answer 34

can I have the complete explanation of the first one with the answer please?? Im really confused with what everyone has wrote... if you could clear it up for me thats be amazing~

Answer 35

command C for copy

Answer 36

ok so that is what i am going to do
in your case \[f(x)=\frac{2x}{2+x}\] and you want \[f(\frac{2x}{2-x})\] so what i am going to do it this:
i am going to use control C to copy \(\frac{2x}{2-x}\) and then i am going to past it in for every \(x\) in \[f(x)=\frac{2x}{2+x}\]
it is going to be messy

Answer 37

its fine, i appreciate it, thank you

Answer 38

i get \[\large f(g(x))=f(\frac{2x}{2-x})=\frac{2\frac{2x}{2-x}}{2+\frac{2x}{2-x}}\]

Answer 39

ok and then what? please;-)

Answer 40

algebra

Answer 41

could you please show me?? and sorry i meant to use :-)

Answer 42

just a sec

Answer 43

\[\frac{2\frac{2x}{2-x}}{2+\frac{2x}{2-x}}\] multiply by \(\frac{2-x}{2-x}\)

Answer 44

\[\frac{2\frac{2x}{2-x}}{2+\frac{2x}{2-x}}\times \frac{2-x}{2-x}\]\[=\frac{4x}{2(2-x)+2x}\]

Answer 45

is that it?

Answer 46

no , algebra in the denominator
you can do that

Answer 47

so it would end up with 4-2x+2x?

Answer 48

aka 4

Answer 49

and \[\frac{4x}{4}=x\]

Answer 50

so i would end up with 4x/ x ?

Answer 51

or wait... is the answer just simply x??

Answer 52

yes

Answer 53

could you please help me with the second too?? thats my last one- you really helped me understand the first by showing me- thanks SO much!!:-) second one please?

Answer 54

sure got logged out

Answer 55

but that was the second one
you need the first one?

Answer 56

\[f(x)=x^4-5,f(x+5)+3=(x+5)^4-5+3\]

Answer 57

ok and then?

Answer 58

i would leave it as \[(x+5)^4-2\] rather than multiplying out

Answer 59

ok

Answer 60

that is all, done

Answer 61

really that is all????

Answer 62

yup