what are two numbers that add to 60 and multiply to -500
@mathmale
@rishavraj
HI!!
Set x+y= 60, and xy=-500. Rearrange and substitute.
you can probably do this by solving \[x^2+60x-500=0\]
@misty1212 that is not nature number after solving the Euation
ok then try @NotTim way
You can use the quadratic formula as well.
\[x=10\left(\sqrt{14}-3\right),\:x=-10\left(3+\sqrt{14}\right)\] After Solveing the Rquation that is the Answer come
\[x+y=60\iff y=60-x\] \[xy=-500\\ x(60-x)=-500\]
@Seratul YEs i have also Solve the Quadratic formula
pretty sure you get the same equation
yes
Finish solving.
no one said the answers had to be integers right?
I don't know the answer
did you get to here \[x(60-x)=-500\]?
What did you get after applying the quadratic formula?
yes but answer is not integer x(60-x)=-500 After solveing the answer is.. \[x=-10\left(\sqrt{14}-3\right),\:x=10\left(3+\sqrt{14}\right)\]
well, they certainly add to 60!!
not sure why you are certain the answers are whole numbers in general, if you solve a quadratic equation, the answers have radicals
@Seratul \[x=-10\left(\sqrt{14}-3\right),\:x=10\left(3+\sqrt{14}\right)\] that is answer after applying Quadratic formula
or \[30-10\sqrt{14}, 30+10\sqrt{14}\]
Then that's your answer. You can continue to solve it if you like to what satellite said.
as @misty1212 said, they add up to 60 for certain you can check to see if they multiply to get \(-500\)
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