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Mathematics 15 Online
OpenStudy (amorfide):

Help me integrate by parts

OpenStudy (amorfide):

\[\int\limits_{0}^{\infty} (e^{-t}t^{n})dt\]

OpenStudy (amorfide):

Apparently the answer is n! if that helps, idk how to get to that

OpenStudy (eliesaab):

You have to get a recurrence formula, or do integration by part n times.

sam (.sam.):

What's this? The answer is a gamma function

OpenStudy (amorfide):

I have to do it via integration by parts, and I have no idea how to succeed

OpenStudy (amorfide):

Would I let u=t^n, or u=e^-t

OpenStudy (eliesaab):

Yes

OpenStudy (amorfide):

wow, which one???

OpenStudy (eliesaab):

If you call \[ I_n=\int_0^\infty t^n e^{-t}dt \]

OpenStudy (eliesaab):

When you do the first integration by part, you get \[ I_n=n I_{n-1} \]

OpenStudy (eliesaab):

You can see where the n! would come from

OpenStudy (amorfide):

oh!

OpenStudy (amorfide):

wait

OpenStudy (amorfide):

\[u=t^{n}\] \[\frac{ du }{ dt } = nt^{n-1}\] \[\frac{ dv }{ dt }= e^{-t}\] \[v=-e^{-t}\] \[[-e^{-t}t^{n}] + n \int\limits_{}^{} e^{-t}t^{n-1}\] the left hand side will always become 0, meaning you will end up with n(n-1)(n-2)...etc thanks!

OpenStudy (eliesaab):

Yes, That is it

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