Hey Hey Hey!!!!!! Fr, though. I need some serious help
Okay using that graph that I made, answer the following question: "Using the figure form part a, prove triangle ABC is congruent to triangle A'B'C'. Show all work."
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Sorry but I can't help you on this. Maybe someone else can help. I am sooo sorry. Hope you get the answer.
@Preetha We need your wisdom.
I know that it is congruent because I reflected, but I have to prove it with numbers.
Y'all are able to open the file, correct?
alright proving the congruency can be acquired by proving the length of the corresponding sides is the same.. you may use the distance formula for that \[D = \sqrt{(y2-y1)^2 + (x2-x1)^2}\] i will do the 1st and you may continue afterwards.. finding length of the side AB and the corresponding side A'B' A(-2,2) B(-4,6) \[AB = \sqrt{(6-2)^2 + (-4+2)^2}\] AB = \[\sqrt[2]{5}\] Now find A'B' A'(2,-2) B'(6,-4) \[A'B' = \sqrt{(-4+2)^2 + (6-2)^2}\] A'B' = \[\sqrt[2]{5}\] Both sides have the same length Thus they are congruent Do the same to the rest of the sides and they will have the same lengths (each side of the pre0image will have the same length as the corresponding side in the image)
And if all the side are same then the triangles are congruent?
indeed by SSS (Side side side ) postulate
SSS Congruence postulate
OHHHHHHK
it's like saying if you move, rotate, shift, or do anything that preserves the triangle's shape and ratio in space, the triangle would still remain a triangle right? so if its lengths have not been scaled up or down either, it's congruent then
http://image.mathcaptain.com/cms/images/45/Congruent-Triangles-Definition.jpg those two triangles look like mirrored versions of each other, but the size is still the same
yeah LannyXX that's called rigid motion. But @iYuko needed a proof with numbers
rigid motion... that makes sense!
In A'B' you subtracted, was that a mistake?
...(6-2)^2
i just went to the last simplification form i skipped the step where it should be (-4 - (-2)) which is eventually (-4+2) and (6-2) is correct just when you substitute the values of the coordinates you will realize
try it out with other sides and show me your work i'll check it for you
okay hold on
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