Question

help

Answer 1

@Will.H

Answer 2

help please

Answer 3

First, rewrite both (1/3) and (81) as powers of 3. (1/3) = 3^?? 81 = 3^??

Answer 4

ok then?

Answer 5

helloo

Answer 6

You haven't responded.

Find the exponent of 3 that gives you (1/3).

Find the exponent of 3 that gives you 81.

Then re-write the original expression.

This alone may be enuf to help you solve this problem.

Sorry, but I have to get off the 'Net now.

Answer 7

3^1 right

Answer 8

3^1=3, so no, that is not correct.

Answer 9

(1/3) = 3^(??)

Answer 10

That's an important basic principle.

Answer 11

3^4=81

Answer 12

\[a ^{-1}=\frac{ 1 }{ a }\]

Answer 13

ok im confused

Answer 14

is it d???

Answer 15

3^4=81. True.

Now replace (1/3) and 81 in the orig. equation . You may then be able to drop the base and solve for the unknown that way.

Sorry, but as I explained before, I need to get off the 'Net. You could check your own answer by substitution. Is the original statement correct?

Answer 16

@Seratul

Answer 17

@Will.H

Answer 18

@Jamierox4ev3r

Answer 19

@legomyego180

Answer 20

@Will.H

Answer 21

@eliesaab

Answer 22

you have
\[(\tfrac13)^{d-5}=81\\
(3^x)^{d-5}=3^4\]
so
\[x(d-5) = 4\]

Answer 23

but what is the \(x\), that solves
\[\tfrac13 = 3^x\]?

Answer 24

\[
\left ( \frac 1 3 \right)^{-4}=81\\
d-5=-4\\
-d+5=4
\]