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A 3.56g sample of Fe is dissolved in 75.0 mL of 6.00 M HCl, forming H2(g) and FeCl2(aq). The Total volume of the resulting solution is 75.2 mL. What is the final concentration of H+ in the solution?
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According to my professor, the final concentration is 0, but I'm not sure how to prove that numerically. I started with getting the moles of HCl from the molarity and volume given, but I don't know what to do from there.
Maybe ask him to do it on the board?
Balanced equation = 1 Fe(s) + 2 HCl (aq) --> 1 FeCl2(aq) + 1 H2(g) Ideally, starting with 0.075 L of 6 M HCl -- Initially our concentration of H+ is [0.45 H+] finding H+ per liter --> [0.45]/0.0752 = 6 H+/Liter initial...
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