Question

I know there is y=ax^2+bx+c, but i never saw someting like ax^2+c. How do I solve that?

Answer 1

You can just isolate x^2 and take the square root...
so set it equal to zero...
0=ax^2+c
-c=ax^2
-c/a=x^2
x= sq. rt plus/minus -c/a ... but you can also use the quadratic formula but b=0

Answer 2

how would I apply that to y=x^2+5
@sunnnystrong?

Answer 3

With that quadratic I would just use the quadratic formula... because you can't take the square root of a negative number.

Answer 4

sorry... -b plus minus (sq. root of b^2+4ac) all divided by 2a

Answer 5

thanks!