The velocities for an accelerating car over a 4-second interval are given below: t(s) | 0 0.5 1.0 1.5 2.0 2.5 3 3.5 4 ----- v(m/s) | 0 15 28 38 47 54 59 61 62 Estimate the distance traveled by the car during this time period by... a) using the velocities at the beginning of the time intervals b) using the velocities at the end of the time intervals
This is a Calculus I problem! Redoing the table... t(s) | 0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0
v(m/s) | 0 15 28 38 47 54 59 61 62
a) left hand riemann sum b) right hand riemann sum
So LHS, RHS and Midpoint basically differ only by the points with which the sub-interval rectangles are drawn?
well anyway idk how to Riemann it w/out a graph T_T
\[\sum_{i=1}^{n} v(t_{i}^{*})\Delta t\]
\(\Delta t\)= difference in consecutive times =.5 \(t_i^*\)=either .5(i-1) or .5*i (left or right)
for for the right \[\sum_{i=1}^{n} v(t_{i}^{*})\Delta t=\sum_{i=1}^{8} v(.5i).5\] \[=15*.5 +28 *.5 + 38 *.5 + 47*.5 + 54 *.5 + 59 *.5 + 61 *.5 + 62*.5\]
o_O
all this formal notation is killing my brain D:
kitty you see that last line that zarkon wrote? it was what I was talking about before where the base of the rectangle is 0.5 and the rhs is made up of the v(m/s) points without the first 0
If I was required to write in \(\Sigma\) notation I may mess things up. But I understand.
Thanks for your help everyone! @Zarkon @Angle
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