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Mathematics 18 Online
OpenStudy (yuii):

The function p(t) represents the value of a new car t years after it was manufactured http://prntscr.com/dg1lb8

OpenStudy (amorfide):

A claims it decreases by 94% each year if you have 10x0.94 you get 9.4 is this 94% less than 10?

OpenStudy (yuii):

No.

OpenStudy (amorfide):

then A is incorrect

OpenStudy (amorfide):

B claims that the initial value is 0.94 P=A(b)^t the initial value is when the power=0 so when t=0 b^0=1 so you have p=A(1) P=A A is your initial value hence 24525 is the initial value hence B is incorrect

OpenStudy (amorfide):

C claims the price increases, but you can clearly see that from 10x0.94=9.4 you decrease the value hence C is incorrect

OpenStudy (amorfide):

if you have t=1 you get 24525x0.94 when t=2 24525x0.94^2 which is 245x0.94x0.94 and as t increases, you multiply by 0.94 that many times hence D is your answer

OpenStudy (yuii):

Thank you.

OpenStudy (3mar):

Let t=0, and you will get the initial value of the car! One year passes, t=1, you get the price of the car decreased by 1471.5$ Another year , t=2, the car's price will be decreased by 2854.71$ Divide (24525-2854.71) by (24525-1471.5) ... what you got? \[\Large \frac{ (24525-2854.71) }{(24525-1471.5)}=\frac{ 47 }{ 50 }=0.94\] what does that mean?

OpenStudy (yuii):

It means that the value of the car decreases by 94% each year?

OpenStudy (3mar):

No, it means that the price of the car of any year is 0.94 of the price of the car of the previous year...so that we divide the price of the car at year 2 by the price at year 1 so the result showed that it was 0.94 of its previous year!

OpenStudy (amorfide):

That was a more interesting approach

OpenStudy (yuii):

Is it still D?

OpenStudy (3mar):

Yes, of course because: 1. all the choices (A, B, and C) are incorrect! 2. @amorfide has said that "hence D is your answer"!

OpenStudy (yuii):

Just making sure, thank you both.

OpenStudy (3mar):

No problem at all! You are welcome! Any Help... Any Time...

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