What is the solution for the system of equations? Use the substitution method to solve. 2x+y=20−5 y=−6x+12
@3mar
Well, I am here. That is a nice question and easy at the same time!
wait its 2x+y=20 -5y= -6x+12
We can use substitution method to plug one equation into the other one!
To do so: - solve for one variable (say y) in one equation. - plug this equation into the other equation. Can you show me how do you understand it?
OH
i get that but i didnt give me anything to plug in
Can you share your works/steps, please?
ok
ok so 2*-6+-5 = 20 ? right
It would better to show me how you did the math, @gigi1103
ok i was just making sure i set it up right
Ok, Take your time.
so 2* - 6 = -12 + -5 = -17
so thats not right is it?
You started with which equation?
the first one
2x+y=20-5
Great! So you solved for y?
OH
yea ill do the other one now
wait
when you solved the first equation for y, what you got?
-17
You did not get me! what I mean is: \[2x+y=20\] \[2x+y-2x=20-2x\] \[y=20-2x\] that is what we need! got it??
OH subtracting from both sides
In other words, 3mar has solved 2x+y=20 for y. This is what you have to do. Substituting (20-2x) for y in the other equation will now elimiinate y; you end up with an equation in x only.
\(\Large y=20-2x\) this is what we will plug it into the other equation!
so for the other one
Yes, to have y in one side "alone" and the other terms in the other side!
Just replace \(y\) in the other equation with this equation [\(\Large y=20-2x\)]
wait im confused
do i plug in the 2x next to the -6
I will simplify it for you! |dw:1481164522702:dw|
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