Question

How many grams of CO are needed to react with an excess of Fe2O3 to produce (210.3 g Fe) 209.7 g Fe? Show your work.

CO (g) + Fe2O3 (s) --> Fe (s) + CO2 (g)

Answer 1

@zepdrix @.Sam.

Answer 2

@Awolflover1 @AloneS @Whitemonsterbunny17

Answer 3

@iwanttogotostanford Hey bro, could you help me out?

Answer 4

no idea how to do this bro i am so sorry.... i would help if i could :-( really have NO idea

Answer 5

I'm horrible at chemistry lol

Answer 6

Eh, worth a shot..thanks though.

Answer 7

Balanced equation:
Fe2O3(s) + 3 CO(g) --> 2 Fe(s) + 3 CO2(g)

Answer 8

So:
CO = Limiting Reagent // Fe2O3 = Excess Reagent
We want to find how many grams of CO produce 210.3 g Fe
& Also.. how many grams of CO Produce 209.7 g of Fe

Recall that:
MM of Fe 58.8 g/mol
MM of CO = 28g/mol

Answer 9

So: We need
158.3 g CO to produce 210.3 g Fe
157.8 g CO to produce 209.7 g Fe

Now we want to find how much Fe2O3 we need -->
Recall that:
MM Fe2O3 = 103.6 g/mol

Answer 10

So:

You need 158.3 g CO & 195.2 g Fe2O3 to make 210.3 g Fe
You need 157.8 g CO & 194.6 g Fe2O3 to make 209.7 g Fe

I'm not sure what they're asking about the excess? Because everything will be reacted

Answer 11

Pls check is it Fe2CO3 or Fe2O3?

Answer 12

Thank you so much! @sunnnystrong

Answer 13

@Wholock NP :D Always happy to help haha

Answer 14

Would you mind helping me with one more problem?

Answer 15

I will try my best :D

Answer 16

It's writing a net ionic equation, I have the reaction balanced, I just need help figuring out which elements are soluble, I think I have an idea, but I want to be sure.

Answer 17

2H3PO4(aq) + 3Ca(OH2)(aq) --> Ca3(PO4)2(aq) + 6H2O(l)

Answer 18

I'm pretty sure PO4 is a spectator ion that can be eliminated, but would OH be one too?

Answer 19

Oh okay awesome:D
So:
Basic solubility rules based on names
Phosphates are insoluble

Answer 20

& Hydroxides bonded with calcium are slightly soluble....

Answer 21

2H3PO4(aq) + 3Ca(OH2)(aq) --> Ca3(PO4)2(s) + 6H2O(l)

Answer 22

So the net ionic equation would be the equation of the ions that participate in the chemistry... the spectator ions essentially just watch the chemistry happen and have no effect on the equilibrium of the equation

3Ca 2+(aq) + 2(PO4)3(aq)- --> Ca3(PO4)2(s)

Answer 23

(PO4)3- *** charge

Answer 24

So basically, the hydrogen ions are soluble, (hyrdogen, duh) but isn't PO4 a spectator ion as well? I mean, it doesn't change.

Answer 25

No... so look at this equation
Acid + Base --> Salt + Water
This is always true**
This insoluble item is always the salt (:

Answer 26

wouldn't worry too much about solubility... :P just remember the form of equations & usually it's pretty simple to find which *Product* is the solid -- the net ionic equation is only the ions of the insoluble species

Answer 27

Thank you so much!