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OpenStudy (sharkfinsoup):
h(x)=(g o f)(x)=1/(x+3)^2 which of the following could be a possible decomposition of h(x)?
A. f(x)=1/x^2;g(x)=x+3
B. f(x)=x+3; g(x)=1/x^2
C.f(x)=x^2; g(x)=x+3
D. f(x)=1/x;g(x)=x+3
9 years ago
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OpenStudy (sharkfinsoup):
I think its C f(x)=x+3; g(x)=1/x^2
Because if you take f(x)=x+3 g(x)=1/x^2 plug the f(x) into the g(x) formula this is what you get g(x)=1/x^2 g(x)=1/(x+3)^2. I think
9 years ago
OpenStudy (unklerhaukus):
Do you mean B or C?
9 years ago
OpenStudy (sharkfinsoup):
oh sorry I meant B
9 years ago
OpenStudy (unklerhaukus):
yeah,
f(x) = x+3, g(x) = 1/x^2
(g o f) (x) = 1/(x+3)^2.
9 years ago
OpenStudy (unklerhaukus):
What would you get with option A?
9 years ago
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OpenStudy (sharkfinsoup):
wouldn't that be (f o g)(x)
9 years ago
OpenStudy (unklerhaukus):
with A: f(x)=1/x^2; g(x)=x+3
fog would work to get the right result:
(f o g)(x) = f(x+3) = 1/(x+3)^2
But what would gof give?
9 years ago
OpenStudy (unklerhaukus):
(gof)(x) = g( f(x) )
= g( 1/x^2 )
= ?
9 years ago
OpenStudy (sharkfinsoup):
wait so it would be (1/x^2)+3
9 years ago
OpenStudy (unklerhaukus):
that's correct
9 years ago
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OpenStudy (unklerhaukus):
As we can now see B is the only correct option.
9 years ago
OpenStudy (sharkfinsoup):
Right that's great. Thank you so much :)
9 years ago
OpenStudy (unklerhaukus):
\[\ddot\smile\]
9 years ago
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