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Mathematics 20 Online
OpenStudy (itrymath):

here it is number 4

OpenStudy (itrymath):

1 sec

OpenStudy (mrs.ambrose614):

Okay

OpenStudy (mrs.ambrose614):

So you need help coming up with what exactly???

OpenStudy (mrs.ambrose614):

Will can help

OpenStudy (itrymath):

lol

OpenStudy (mrs.ambrose614):

Lol I give up I haven't gotten to that do u do flvs online???

OpenStudy (itrymath):

OpenStudy (itrymath):

so lots of people didnt understand how to do this only Irish but he proposed something i've never seen before nor heard of

OpenStudy (will.h):

For part A : This situation can be represented as exponential function because we have a constant decreasing rate and a principal to start with.

OpenStudy (will.h):

Dude. I'll help u with the 1st only

OpenStudy (itrymath):

okay

OpenStudy (mrs.ambrose614):

Wouldn't a be exponential

OpenStudy (mrs.ambrose614):

Because it shows that is decreasing

OpenStudy (mrs.ambrose614):

And wouldn't two be

OpenStudy (itrymath):

its $110 increase every year

OpenStudy (itrymath):

I think its linear

OpenStudy (will.h):

Part B: The formal shape of the exponential function is F(x) = P(1 + r)^x Where P is the principal which is 1200 And r is the rate of decay which is 2.5% Based on that adjust the rate of change 100 - 2.5 = 97.5% Therefore R = 0.975 Now substitute F(x) = 1200(1 - 0.975)^x

OpenStudy (will.h):

What u guys talking about?

OpenStudy (itrymath):

well part is lineaer isnt it

OpenStudy (itrymath):

how is it exponential ??

OpenStudy (itrymath):

its increasing

OpenStudy (will.h):

Linear function requires a slope. A slope can be derived when the function contains constant change in this case. The change isn't constant. Check the graph of the function I just derived

OpenStudy (will.h):

Although it isn't increasing. It is decreasing by rate if 2.5%

OpenStudy (will.h):

Make sense?

OpenStudy (itrymath):

ooohh i remember it has to have a constant to have slope yes yes of course sorry!!!

OpenStudy (itrymath):

my teacher did talk about this

OpenStudy (itrymath):

and whats the other possibility when its doesnt have a constant rate of change ?

OpenStudy (will.h):

There are different types of functions. But in your current case and math methodologies (Algebra 1 A) you'll be working with Linear and exponential function.. So if it's not linear it'll be exponential

OpenStudy (itrymath):

okay thanks

OpenStudy (will.h):

Do you need part C or you got it?

OpenStudy (itrymath):

i use the function you gave in party B and substitute "x" with 20 yes?

OpenStudy (itrymath):

part *

OpenStudy (will.h):

Part C is quite different than B.. Part C is linear function. Linear function form F(x) = mx + b Where m is slope and B is Y intercept. Since they said "decrease by 3 lumens per (unit)" Means the rate of change aka slope is constant since the rate is per unit. Therefore the slope is -3 (because it decrease) and the y intercept is 1200 because that's the kick off number. Thus the function would be linear indeed for part C F(x) = -3x + 1200

OpenStudy (itrymath):

okay thanks im alaways wrong xD gtg now cyq

OpenStudy (will.h):

Good luck

OpenStudy (itrymath):

is there anything i will need to do to finish ?

OpenStudy (itrymath):

part A right?

OpenStudy (will.h):

For the 1st question u posted I answered all parts

OpenStudy (itrymath):

@jim_thompson5910 in part B why did he subtract 100 from 2.5% ?

jimthompson5910 (jim_thompson5910):

Because it's similar to the other idea of having it in the form 1+r r is a negative value, in this case r = -2.5% = -0.025 1+r = 1+(-0.025) = 1-0.025 = 0.975 so if you want to decrease a quantity by 2.5%, you multiply that value by 0.975

OpenStudy (itrymath):

oh i get

OpenStudy (itrymath):

so what if the decreasing value per usit was lets say 25.5%

jimthompson5910 (jim_thompson5910):

then r = -25.5% = -0.255

jimthompson5910 (jim_thompson5910):

yes correct

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