Question

Convert the equation from Polar to Rectangular form: 5= 1/ 4cos(theta)-3sin(theta)

Answer 1

Is it supposed to be
\[5=\frac{1}{4\cos\theta}-3\sin\theta\quad\text{or}\quad5=\frac{1}{4\cos\theta-3\sin\theta}\]

Answer 2

typo.. the 5 is supposed to be an r. so: \[r=\frac{ 1 }{ 4\cos \theta-3\sin \theta }\]

Answer 3

\[x=r \cos \theta ~~~~~,~~~y=rsin \theta\]

Answer 4

a. \[y=\frac{ 4 }{ 3 }x-1\]
b. y=4x+1
c. \[y=\frac{ 4 }{ 3 }x-\frac{ 1 }{ 3 }\]
d. y=12x+3

Answer 5

hint multiply both sides by 4 cos(theta)-3 sin(theta)
then make the replacements @Nnesha mentioned

Answer 6

divide both sides by r
then put \[r \cos \theta=x,r \sin \theta=y \]

Answer 7

hmm i got c.

you must know these
x= rcostheta
y=rsintheta