Convert the equation from Polar to Rectangular form: 5= 1/ 4cos(theta)-3sin(theta)

Question

holsteremission · Answer

Is it supposed to be
$$5=\frac{1}{4\cos\theta}-3\sin\theta\quad\text{or}\quad5=\frac{1}{4\cos\theta-3\sin\theta}$$

onthecly2 · Answer

typo.. the 5 is supposed to be an r. so: $$r=\frac{ 1 }{ 4\cos \theta-3\sin \theta }$$

nnesha · Answer

$$x=r \cos \theta ~~~~~,~~~y=rsin \theta$$

onthecly2 · Answer

a. $$y=\frac{ 4 }{ 3 }x-1$$ 
b. y=4x+1
c. $$y=\frac{ 4 }{ 3 }x-\frac{ 1 }{ 3 }$$
d. y=12x+3

myininaya · Answer

hint multiply both sides by 4 cos(theta)-3 sin(theta)
then make the replacements @Nnesha mentioned

sshayer · Answer

divide both sides by r
then put $$r \cos \theta=x,r \sin \theta=y $$

marcelie · Answer

hmm i got c.

you must know these
x= rcostheta
y=rsintheta 

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