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Mathematics 13 Online
OpenStudy (seratul):

Why are all inverse functions a One-To-One Function??

OpenStudy (seratul):

One-To-One functions are functions that are true for both ways. For instance- All x values have only one y value, and all y values have only one x value.

OpenStudy (tkhunny):

\(f(x)\) must pass the vertical line test. \(f^{-1}(x)\) must pass the horizontal line test. \(f(f^{-1}(x)) = x\) \(f^{-1}(f(x)) = x\) There's an explanation in there, somewhere.

OpenStudy (seratul):

Not sure what that explanation is xD.

OpenStudy (seratul):

In my notes, I wrote that A function only has an inverse if it is 1 to 1. Otherwise, it is just a reflection of y=x. Do you know what that means?

OpenStudy (seratul):

I should've asked but I thought I understood it. But as I'm doing the homework, I can't seem to understand the logic behind that.

OpenStudy (tkhunny):

Lean more on the word "function".

OpenStudy (seratul):

That doesn't really help but okay :'(

OpenStudy (mathmale):

In this situation, "one to one" characterizes a function: For every input (within the domain) to a function, there is exactly ONE output. Such a function has an inverse. On the other hand, if for some particular input to the relation (not function), there are two or more output (y-) values, the relation is NOT one to one and does not have an inverse.

OpenStudy (mathmale):

If you start with a function f(x) and find its inverse, the inverse has to be one to one. Else, you could not work backward from the inverse function to obtain the original function.

OpenStudy (seratul):

Okay, I think I got it, thank you.

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