Why are all inverse functions a One-To-One Function??
One-To-One functions are functions that are true for both ways. For instance- All x values have only one y value, and all y values have only one x value.
\(f(x)\) must pass the vertical line test. \(f^{-1}(x)\) must pass the horizontal line test. \(f(f^{-1}(x)) = x\) \(f^{-1}(f(x)) = x\) There's an explanation in there, somewhere.
Not sure what that explanation is xD.
In my notes, I wrote that A function only has an inverse if it is 1 to 1. Otherwise, it is just a reflection of y=x. Do you know what that means?
I should've asked but I thought I understood it. But as I'm doing the homework, I can't seem to understand the logic behind that.
Lean more on the word "function".
That doesn't really help but okay :'(
In this situation, "one to one" characterizes a function: For every input (within the domain) to a function, there is exactly ONE output. Such a function has an inverse. On the other hand, if for some particular input to the relation (not function), there are two or more output (y-) values, the relation is NOT one to one and does not have an inverse.
If you start with a function f(x) and find its inverse, the inverse has to be one to one. Else, you could not work backward from the inverse function to obtain the original function.
Okay, I think I got it, thank you.
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