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So: in this problem you are going to be using the inverse square law \[\frac{ I1 }{ I2 }=\frac{ (d _{2})^2 }{ (d _{1})^2 }\] *Substitute \[d1=5meters\] \[d2=20meters\] \[I1=2Sv/h\] \[I2=?\] \[\frac{ 2Sv/h }{ I2 }=\frac{ (20meters)^2 }{ (5meters)^2 }\] *Solve for I2 \[I2= 0.125 Sv/h\]
@MTALHAHASSAN2 still there? haha
LOL what is d stands for?
d1 & d2 = two different distances from the source (point gamma source)
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i know I is the n intensity but what is d thou?
oh
that's make scene thanks a lot
yep :D just plug in & solve XD
Anytime :D
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