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Mathematics 11 Online
OpenStudy (mtalhahassan2):

I need help!

OpenStudy (mtalhahassan2):

http://prntscr.com/dir31a

OpenStudy (sunnnystrong):

So: in this problem you are going to be using the inverse square law \[\frac{ I1 }{ I2 }=\frac{ (d _{2})^2 }{ (d _{1})^2 }\] *Substitute \[d1=5meters\] \[d2=20meters\] \[I1=2Sv/h\] \[I2=?\] \[\frac{ 2Sv/h }{ I2 }=\frac{ (20meters)^2 }{ (5meters)^2 }\] *Solve for I2 \[I2= 0.125 Sv/h\]

OpenStudy (sunnnystrong):

@MTALHAHASSAN2 still there? haha

OpenStudy (mtalhahassan2):

LOL what is d stands for?

OpenStudy (sunnnystrong):

d1 & d2 = two different distances from the source (point gamma source)

OpenStudy (mtalhahassan2):

i know I is the n intensity but what is d thou?

OpenStudy (mtalhahassan2):

oh

OpenStudy (mtalhahassan2):

that's make scene thanks a lot

OpenStudy (sunnnystrong):

yep :D just plug in & solve XD

OpenStudy (sunnnystrong):

Anytime :D

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