The figure below shows a trapezoid, ABCD, having side AB parallel to side DC. The diagonals AC and BD intersect at point O. ABCD is a trapezoid with DC parallel to AB. Diagonals AC and DB intersect at point O. If the length of AO is double the length of CO, the length of BO is half of the length of AB double the length of DO one-fourth the length of AC equal to the length of AO
Since both of the triangles in the trapezoid are similar triangles, we can assume that they are proportionate, meaning that the correct answer would be: double the length of DO. Since they are similar.
thank you, can you help me with more?
@duckerstar146
Of course!
thank you!!
The figure shows three right triangles. Triangles PQS, QRS, and PRQ are similar. Theorem: If two triangles are similar, the corresponding sides are in proportion. Figure shows triangle PQR with right angle at Q. Segment PQ is 4 and segment QR is 9. Point S is on segment PR and angles QSP and QSR are right angles. Using the given theorem, which two statements help to prove that if segment PR is x, then x2 = 97? Segment PR • segment PS = 16 Segment PR • segment SR = 36 Segment PR • segment PS = 36 Segment PR • segment SR = 81 Segment PR • segment PS = 16 Segment PR • segment SR = 81 Segment PR • segment PS = 81 Segment PR • segment SR = 16
Ok, let's first start by finding PR: Which is....
uhhhhh, im not really sure, i suck at math
Sorry, my internet bugged out for a second, lol, anyways, we can first tell that the square root of 97 is PR, If you have any questions, I'll be here
So PR = Square Root of 97
ok thank you!!
Next, we have to set up proportions to find PS
Let PS be the variable x, and so SR = sqrt(97) - x
is that it?
Well not yet, next, we have to find two pairs of equal angles, to set up ratios on both of their sides
oohhhh
We can use PS/PQ = PQ/PR
okay, i tried solving it, is it C?
Correct!
YAYYY, so it is Segment PR • segment PS = 16 Segment PR • segment SR = 81
Yes it is
thank you!!
No Problem
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