Getting confused about this question..
http://prnt.sc/djih37

Question

Getting confused about this question..
http://prnt.sc/djih37

nevermind_justschool · Answer

@mathstudent55

nevermind_justschool · Answer

@misty1212

emeric · Answer

just make y the subject. like
y=6-3x
and
y=(-9-2x)/3

nevermind_justschool · Answer

For the first one does x=2 
e-e

ilovepuppieslol · Answer

http://www.wolframalpha.com/widgets/view.jsp?id=ae438682ce61743f90d4693c497621b7

nevermind_justschool · Answer

But just for y though, right?

ilovepuppieslol · Answer

yea

nevermind_justschool · Answer

Will this work then?

nevermind_justschool · Answer

@Zarkon Can you please help me

imqwerty · Answer

Umm the boxes are supposed to be filled with equations
So i think in the first box you have to write y in terms of x that you get from first equation 
And in the second box you have to write y in terms of x that you get from second equation

mathmale · Answer

First equation is 3x+y=6.  Your job is to solve this equation for y.  That means you must isolate y on the left side of this equation.  Start by subtracting 3x from both sides of this equation.  Please share your result.

nevermind_justschool · Answer

y=-3x+6 
y=-2/3x-3

mathmale · Answer

Type these results into the boxes in your illustration (picture).

For Equation 1, type in y=-3x+6
For Equation 2, type in y=(2/3)x-3

mathmale · Answer

Both of your answers are correct.