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Mathematics 17 Online
wo1f0mon:

HELPPPPPPP

wo1f0mon:

http://prntscr.com/djupy6

psirockin2:

can't. my security stuff flags printscreen

kittybasil:

@psirockin2 try this: 9993be30ad6e4ba0a5e1f809038df6aa.png

psirockin2:

still doesn't show...

wo1f0mon:

...

kittybasil:

welp @wo1f0mon HINT:\[a^0=1\] no matter what \(a\) is

kittybasil:

also...\[(a^b)^c=a^{b(c)}\]

wo1f0mon:

b and c are out then

wo1f0mon:

i think its A am i right?

wo1f0mon:

@kittybasil

kittybasil:

@wo1f0mon wrote:
b and c are out then
Wrong. One of those is correct.

kittybasil:

Here are the exponent rules that apply:\[(x^a)^b=x^{a\times b}\]\[x^0=1\]

wo1f0mon:

no its a

kittybasil:

\[\Large{(x^{a})^{b}=x^{a\times b}}\]

kittybasil:

\[\Large{(x^a)^b\ne x^{(a+b)}}\]

kittybasil:

\[2\times3\stackrel{?}{=}5\]

wo1f0mon:

oh ok den

wo1f0mon:

c

kittybasil:

\[\left(\frac{2^2\times1}{7}\right)^3=\frac{(2^2)^3\times1^3}{7^3}=\frac{2^6\times1}{343}\] refer to this for information

kittybasil:

\[\Large{\checkmark}\]

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